stream commando

Commando war Input:Standard Input Output:Standard output "Waiting for orders we held in the wood, word from thefront never came By evening the sound of the gunfire was miles away Ah softly We moved through the shadows, slip awaythrough the trees Crossing their lines in the mists in the fields on ourhands and our knees And all that I ever, was able to see The fire in the air, glowing red, silhouetting thesmoke on the breeze" Thereis a war and it doe

There is a war and it doesn't look very promising for your country. now it's time to act. you have a commando squad at your disposal and planning an ambush on an important enemy camp located nearby. you have N Soldiers in your squad. in your master-plan, every single soldier has a unique responsibility and you don't want any of your soldier to know the plan for other soldiers so that everyone can focus on his task only. in order to enforce this, you b

=='-') sign=-1; Ch=GetChar ();} - while(ch>='0'ch'9') {v=v*Ten+ch-'0'; Ch=GetChar ();} - returnv*=Sign ; - } in Const intn=1e6+Ten; -typedefLong LongLL; to /******************tamplate*********************/ + LL F[n],x[n],s[n]; - intq[n],a,b,c; the DoubleSlopintKintj) { * return Double(f[j]-f[k]+a* (S[j]*s[j]-s[k]*s[k]) +b* (s[k]-s[j])/ $ Double(2*a* (s[j]-s[k]));Panax Notoginseng } - intMain () { the #ifndef Online_judge +Freopen ("1911.in","R", stdin); AFreopen ("1911.out",

Topic linksSlope optimization1#include 2#include 3#include string>4#include 5#include 6 #defineRe (I,L,R) for (int i= (l); i7 using namespacestd;8typedefLong LongLL;9TemplateTen voidInin (Q x) One { Ax=0;intf=0;CharCh=GetChar (); - while(ch'0'|| Ch>'9'){if(ch=='-') f=1; ch=GetChar ();} - while(ch>='0'ch'9') x= (x3) + (x1) +ch-'0', ch=GetChar (); thex=f?-x:x; - } - intn,a,b,c; -LL sum[1000010],x[1000010],y[1000010],aa[1000010],dp[1000010]; + intq[1000010]; -LL F (ConstLL a) {returnA *A;

the summary is the foundation of the thick accumulation of thin hair, this is the eternal truth. From quantitative to qualitative change depends on the summary of the process you can break through and deep, perhaps a little bit less, when the qualitative changes in the attitude and approach to the problem will have a broader space, which is what we usually call "enlightened." Precipitate what? We should not only summarize the knowledge points, but also summarize the methods, means, mentalit

"Title translation":Problem analysis: Because tasks can be executed in parallel, it is intuitively a task that takes a long time to prioritize deployment. But this to the topic also gives you the task of time, so easy to let people think more.There are only two possible cases for tasks x and Y, regardless of the time it takes to account for the task. X ends before y, and x ends after Y. Here it is discussed that X is done before Y.When x and Y positions are not swapped, the completion time is: B

"Waiting for orders we held in the wood,Word from the front never cameBy evening the sound of the gunfire was miles awayAh softly we moved through the shadows, slip away through the treesCrossing their lines in the mists of the fields on our hands and our kneesAnd all that I ever, is able to seeThe fire in the air, glowing red, silhouetting the smoke on the Breeze "This is the most poetic and passionate about the UVA topic is rare Brief EncounterThe hermit didn't think of the previous days Qzy s

group of data under the number of N (1OutputFor each group of data for the group, output the shortest time for all tasks to complete. The specific output format is shown in the sample, beginning with case, after case output the current data ordinal, and then output the answer.Sample Input32 53 22 133 34 4 5 50Sample OutputCase 1:8case 2:15#include #include#includeusing namespacestd;structnode{intB,j;} wor[1005];BOOLCMP (Node w1,node W2) {returnW1.j>W2.J;}intMain () {intN; intt=1; while((scanf

n a subordinate, each of the men to complete a task. Each task must be B time confessed, J time execution.Cannot give two subordinates simultaneous account of the task.Outputs the shortest time to complete all tasks.Uva 11792#include 　　[Water] UVA 11792 Commando War

Test instructions: There are n subordinates, confessed each of his subordinates to complete his corresponding tasks need bi time, and then complete the task requires Ji time,Choose the order of the tasks, make the total time to spend the leastBecause in any case, the time required to confess the N*BI is to be spent,Then let the person who completes the task take a long time to do first, will j in descending order, update each person's task to complete the time spent1#include 2#include 3#include

Greedy method, the time of the execution of the task J longer should be confessed first. The correctness can be proved by the adjacent Exchange method. In fact, for two people, to make the total time is the shortest, it is necessary to do two things at the same time the longest time.#include #include#include#include#includestring>#include#include#includeSet>#include#include#include#include#include#includeusing namespacestd;#definePII pair#defineLL Long Long intConst inteps=1e-8;Const intinf=1000

I. Io and stream Data input and output (I/O for input/output)The input and output of standard input devices and standard output devices are referred to as standard I/OThe input and output of files stored on an external disk are referred to as files I/O.The input and output of the specified string bucket in the memory are referred to as string I/O. The process of data input and output can be visually viewed as a stream.The operation for retrieving dat